The format you are practising for
One consequence of the adaptive structure is worth internalising before you practise. Module 1 is fixed difficulty for every test taker, and it determines which version of Module 2 you receive. That makes the early questions disproportionately valuable - not because they are worth more points directly, but because they decide which scoring range is still available to you.
The practical implication is that rushing Module 1 to bank time for Module 2 is exactly backwards.
| Item | Detail |
|---|---|
| Questions | 44 |
| Time | 70 minutes |
| Structure | Two modules of about 22 questions; Module 2 is adaptive |
| Content domains | Algebra; Advanced Math; Problem-Solving and Data Analysis; Geometry and Trigonometry |
| Calculator | Built-in Desmos graphing calculator, available on all questions |
| Provided | On-screen reference sheet with common formulas |
Practice: algebra
If 2x + 3y = 19 and y = x + 3, what is the value of x?
x = 2. Substitute the second equation into the first: 2x + 3(x + 3) = 19, so 2x + 3x + 9 = 19, giving 5x = 10 and x = 2. Substitution is almost always faster than elimination when one variable is already isolated - recognising which method the question has set up for you is where the time is saved.
A gym charges a one-time joining fee plus a fixed monthly rate. The total cost in dollars after m months is C = 45m + 60. What does 60 represent?
The one-time joining fee - the cost when m = 0, before any monthly charges. This is an interpretation question, and there is nothing to calculate. The digital SAT contains a lot of these: given a linear model, identify what the slope or the intercept means in the situation described. Train the habit of asking what happens at zero for the constant, and what happens per one unit for the coefficient.
For what value of k does the system 2x + 3y = 7 and 4x + ky = 9 have no solution?
k = 6. A linear system has no solution when the lines are parallel: the coefficients are proportional but the constants are not. Doubling the first equation gives 4x + 6y = 14, so k = 6 makes the left sides proportional, and since 9 does not equal 14 the lines are parallel rather than identical. If the second equation had been 4x + 6y = 14, the system would have infinitely many solutions instead.
Practice: advanced math and geometry
Which form of f(x) = x squared minus 6x plus 5 displays the minimum value of the function as a constant?
Vertex form: f(x) = (x - 3) squared minus 4. Complete the square by halving the coefficient of x, which gives 3, then subtracting 3 squared: x squared minus 6x plus 9 minus 9 plus 5. The minimum value is negative 4, occurring at x = 3. The SAT asks about forms of a quadratic frequently - factored form shows the zeros, vertex form shows the minimum or maximum, and standard form shows the y-intercept.
A right triangle has legs of length 6 and 8. What is the sine of the angle opposite the leg of length 6?
0.6. The hypotenuse is 10 by the Pythagorean theorem, and sine is the opposite side over the hypotenuse, so 6 divided by 10. Recognising the 3-4-5 triangle scaled by 2 saves you the calculation entirely - the 3-4-5 and 5-12-13 families appear often enough to be worth recognising on sight.
Practice: problem-solving and data analysis
This domain produces the questions students most often get wrong while feeling confident, because the arithmetic is easy and the reasoning is not.
A shirt's price is reduced by 20%. The sale price is then reduced by a further 25%. The final price is what percent of the original?
60%. Successive percentage changes multiply rather than add: 0.80 times 0.75 equals 0.60. The tempting wrong answer is 55%, from adding the two reductions to get 45% off. The second discount applies to the already-reduced price, not to the original, and the SAT tests this specific misconception repeatedly.
For a set of data on hours studied and test score, the line of best fit is y = 2.4x + 15. What does 2.4 represent?
The predicted increase in score for each additional hour studied. Two cautions the SAT expects you to hold: this is a predicted change, not a guaranteed one, and it describes an association rather than proving that studying causes the score to rise. Questions in this domain often hinge on whether an answer choice overstates a correlation as causation.
A car travels 150 miles in 2.5 hours. At the same rate, how far does it travel in 4 hours?
240 miles. The rate is 150 divided by 2.5, which is 60 miles per hour, and 60 times 4 is 240. Set up unit rates deliberately rather than cross-multiplying by reflex - once you have 60 miles per hour written down, any follow-up question about a different duration takes seconds.
Practice this now
When not to reach for the calculator
Because Desmos is available on all 44 questions, students often use it on all 44 questions. That is a pacing error rather than a strategy. Typing a straightforward linear equation into a graphing calculator costs more time than solving it, and the setup cost is paid on every question.
The calculator earns its keep on a narrower set: solving systems by graphing intersections, finding zeros of an awkward quadratic, checking a messy calculation you have already done by hand, and reading values off a function you would otherwise have to sketch.
It is close to useless on interpretation questions - which is a growing share of the section - because there is nothing to compute. If a question asks what a constant means, the calculator has no role at all.